0=0.2x^2-3x+3.5625

Solution for 0=0.2x^2-3x+3.5625 equation:

0=0.2x^2-3x+3.5625

We move all terms to the left:

0-(0.2x^2-3x+3.5625)=0

We add all the numbers together, and all the variables

-(0.2x^2-3x+3.5625)=0

We get rid of parentheses

-0.2x^2+3x-3.5625=0

a = -0.2; b = 3; c = -3.5625;
Δ = b2-4ac
Δ = 32-4·(-0.2)·(-3.5625)
Δ = 6.15
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{6.15}}{2*-0.2}=\frac{-3-\sqrt{6.15}}{-0.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{6.15}}{2*-0.2}=\frac{-3+\sqrt{6.15}}{-0.4}
$